**Question: How many triangles can be formed from a set of 8 points, where 5 of these points are collinear.**

My Analogy: Since 5 points are collinear and 3 points randomly placed, then we can pick 2 points from the collinear part and 1 from random points. That means, ^{5}C_{2}*^{3}C_{1}/2!*1! + 1. Plus 1 because all the 3 random points can also form a triangle.

I need to know whether I am correct with this analogy or not. @Ishvinder