First and foremost, I did not understand the question.
I thought I will make out by understanding the solution. But I did not understand the solution as well. Can you explain, how does the below code works, please?
def func(x):
return x**2
def find_derivative(data):
func, x_a = data
delta_x = 0.000001
f_x_a = func(x_a)
f_delta_x = func(x_a + delta_x)
return ((f_delta_x - f_x_a)/delta_x, x_a, f_x_a, delta_x)
data = (func, 6)
find_derivative(data)
Hi @Ashwin,
Here data is a tuple containing the function, and the integer, which is further been passed to find_derivative function.
The latter function uses a simple formula to compute the derivative for the given function and the value, and returns a tuple containing : Derivative, integer value(x), f(x), delta_x.
Thanks @Ishvinder!
I understood every word of your answer. But I am still not able to understand the solution.
Specifically, how does this work? - data = (func, 6) Is the one that we defined at the beginning? Can we pass a function as an argument?
Then how does func, x_a = data work? Why do we have to make such an assignment?
When we can call a function in another function, why is it necessary?
How did we arrive at the value delta_x = 0.000001?
Sorry, if the questions sound dumb.
func, x_a is used to simply unwrap the tuple argument passed to the function.func as an argument, as there can be any function with a given value, for which we may want to find derivative. In order to make the derivative function generic, it’s used like this.