Week 7: Percentile Calculation: Special case

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In the above case what would happen if the 20th item’s value was 62?

Then Y_80 would have been 62 + 0(62-62) = 62

So, that would mean even the 20th element will also be part of the 80th percentile?

Not every time, had there been a fractional non-zero part somehow, then it would have been changed.